4(y+3)=-2(8y-5)+2y

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Solution for 4(y+3)=-2(8y-5)+2y equation: 



4(y+3)=-2(8y-5)+2y

We move all terms to the left:

4(y+3)-(-2(8y-5)+2y)=0

We multiply parentheses

4y-(-2(8y-5)+2y)+12=0



We calculate terms in parentheses: -(-2(8y-5)+2y), so:

-2(8y-5)+2y

We add all the numbers together, and all the variables

2y-2(8y-5)

We multiply parentheses

2y-16y+10

We add all the numbers together, and all the variables

-14y+10

Back to the equation:

-(-14y+10)



We get rid of parentheses

4y+14y-10+12=0

We add all the numbers together, and all the variables

18y+2=0

We move all terms containing y to the left, all other terms to the right

18y=-2

y=-2/18

y=-1/9

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