19=3(b+4)+1

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Solution for 19=3(b+4)+1 equation: 



19=3(b+4)+1

We move all terms to the left:

19-(3(b+4)+1)=0



We calculate terms in parentheses: -(3(b+4)+1), so:

3(b+4)+1

We multiply parentheses

3b+12+1

We add all the numbers together, and all the variables

3b+13

Back to the equation:

-(3b+13)



We get rid of parentheses

-3b-13+19=0

We add all the numbers together, and all the variables

-3b+6=0

We move all terms containing b to the left, all other terms to the right

-3b=-6

b=-6/-3

b=+2

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