4(y+3)+2=38

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Solution for 4(y+3)+2=38 equation: 



4(y+3)+2=38

We move all terms to the left:

4(y+3)+2-(38)=0

We add all the numbers together, and all the variables

4(y+3)-36=0

We multiply parentheses

4y+12-36=0

We add all the numbers together, and all the variables

4y-24=0

We move all terms containing y to the left, all other terms to the right

4y=24

y=24/4

y=6

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