-3(1+n)-2n=-6(n+2)

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Solution for -3(1+n)-2n=-6(n+2) equation:



-3(1+n)-2n=-6(n+2)
We move all terms to the left:
-3(1+n)-2n-(-6(n+2))=0
We add all the numbers together, and all the variables
-3(n+1)-2n-(-6(n+2))=0
We add all the numbers together, and all the variables
-2n-3(n+1)-(-6(n+2))=0
We multiply parentheses
-2n-3n-(-6(n+2))-3=0
We calculate terms in parentheses: -(-6(n+2)), so:
-6(n+2)
We multiply parentheses
-6n-12
Back to the equation:
-(-6n-12)
We add all the numbers together, and all the variables
-5n-(-6n-12)-3=0
We get rid of parentheses
-5n+6n+12-3=0
We add all the numbers together, and all the variables
n+9=0
We move all terms containing n to the left, all other terms to the right
n=-9

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