4(y+2)=3(2-y)

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Solution for 4(y+2)=3(2-y) equation: 



4(y+2)=3(2-y)

We move all terms to the left:

4(y+2)-(3(2-y))=0

We add all the numbers together, and all the variables

4(y+2)-(3(-1y+2))=0

We multiply parentheses

4y-(3(-1y+2))+8=0



We calculate terms in parentheses: -(3(-1y+2)), so:

3(-1y+2)

We multiply parentheses

-3y+6

Back to the equation:

-(-3y+6)



We get rid of parentheses

4y+3y-6+8=0

We add all the numbers together, and all the variables

7y+2=0

We move all terms containing y to the left, all other terms to the right

7y=-2

y=-2/7

y=-2/7

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