28/2(3x-4)=-2x+40

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Solution for 28/2(3x-4)=-2x+40 equation: 



28/2(3x-4)=-2x+40

We move all terms to the left:

28/2(3x-4)-(-2x+40)=0



Domain of the equation: 2(3x-4)!=0

x∈R



We get rid of parentheses

28/2(3x-4)+2x-40=0

We multiply all the terms by the denominator


2x*2(3x-4)-40*2(3x-4)+28=0

Wy multiply elements

4x^2(3-80x(3+28=0

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