4(y+2)-6(y+1)=2(y+4)+2

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Solution for 4(y+2)-6(y+1)=2(y+4)+2 equation: 



4(y+2)-6(y+1)=2(y+4)+2

We move all terms to the left:

4(y+2)-6(y+1)-(2(y+4)+2)=0

We multiply parentheses

4y-6y-(2(y+4)+2)+8-6=0



We calculate terms in parentheses: -(2(y+4)+2), so:

2(y+4)+2

We multiply parentheses

2y+8+2

We add all the numbers together, and all the variables

2y+10

Back to the equation:

-(2y+10)



We add all the numbers together, and all the variables

-2y-(2y+10)+2=0

We get rid of parentheses

-2y-2y-10+2=0

We add all the numbers together, and all the variables

-4y-8=0

We move all terms containing y to the left, all other terms to the right

-4y=8

y=8/-4

y=-2

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