5(y-1)=-3(y-4)-1

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Solution for 5(y-1)=-3(y-4)-1 equation: 



5(y-1)=-3(y-4)-1

We move all terms to the left:

5(y-1)-(-3(y-4)-1)=0

We multiply parentheses

5y-(-3(y-4)-1)-5=0



We calculate terms in parentheses: -(-3(y-4)-1), so:

-3(y-4)-1

We multiply parentheses

-3y+12-1

We add all the numbers together, and all the variables

-3y+11

Back to the equation:

-(-3y+11)



We get rid of parentheses

5y+3y-11-5=0

We add all the numbers together, and all the variables

8y-16=0

We move all terms containing y to the left, all other terms to the right

8y=16

y=16/8

y=2

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