4(y+1)=7y+19

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Solution for 4(y+1)=7y+19 equation:



4(y+1)=7y+19
We move all terms to the left:
4(y+1)-(7y+19)=0
We multiply parentheses
4y-(7y+19)+4=0
We get rid of parentheses
4y-7y-19+4=0
We add all the numbers together, and all the variables
-3y-15=0
We move all terms containing y to the left, all other terms to the right
-3y=15
y=15/-3
y=-5

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