8x(3x-2)-5x(4x-5)=4x2+18

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Solution for 8x(3x-2)-5x(4x-5)=4x2+18 equation: 



8x(3x-2)-5x(4x-5)=4x^2+18

We move all terms to the left:

8x(3x-2)-5x(4x-5)-(4x^2+18)=0

We multiply parentheses

24x^2-20x^2-16x+25x-(4x^2+18)=0

We get rid of parentheses

24x^2-20x^2-4x^2-16x+25x-18=0

We add all the numbers together, and all the variables

9x-18=0

We move all terms containing x to the left, all other terms to the right

9x=18

x=18/9

x=2

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