4(y+1)-7=3(y-1)=y

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Solution for 4(y+1)-7=3(y-1)=y equation: 



4(y+1)-7=3(y-1)=y

We move all terms to the left:

4(y+1)-7-(3(y-1))=0

We multiply parentheses

4y-(3(y-1))+4-7=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We add all the numbers together, and all the variables

4y-(3y-3)-3=0

We get rid of parentheses

4y-3y+3-3=0

We add all the numbers together, and all the variables

y=0

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