16d=8d(d+4)

Solution for 16d=8d(d+4) equation:

16d=8d(d+4)

We move all terms to the left:

16d-(8d(d+4))=0


We calculate terms in parentheses: -(8d(d+4)), so:

8d(d+4)

We multiply parentheses

8d^2+32d

Back to the equation:

-(8d^2+32d)


We get rid of parentheses

-8d^2+16d-32d=0

We add all the numbers together, and all the variables

-8d^2-16d=0

a = -8; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·(-8)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*-8}=\frac{0}{-16}
=0
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*-8}=\frac{32}{-16}
=-2
$