4(y+1)-7=3(y+1)+y

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Solution for 4(y+1)-7=3(y+1)+y equation: 



4(y+1)-7=3(y+1)+y

We move all terms to the left:

4(y+1)-7-(3(y+1)+y)=0

We multiply parentheses

4y-(3(y+1)+y)+4-7=0



We calculate terms in parentheses: -(3(y+1)+y), so:

3(y+1)+y

We add all the numbers together, and all the variables

y+3(y+1)

We multiply parentheses

y+3y+3

We add all the numbers together, and all the variables

4y+3

Back to the equation:

-(4y+3)



We add all the numbers together, and all the variables

4y-(4y+3)-3=0

We get rid of parentheses

4y-4y-3-3=0

We add all the numbers together, and all the variables

-6!=0

There is no solution for this equation

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