4(x-5)=10-2(x+3)

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Solution for 4(x-5)=10-2(x+3) equation:



4(x-5)=10-2(x+3)
We move all terms to the left:
4(x-5)-(10-2(x+3))=0
We multiply parentheses
4x-(10-2(x+3))-20=0
We calculate terms in parentheses: -(10-2(x+3)), so:
10-2(x+3)
determiningTheFunctionDomain -2(x+3)+10
We multiply parentheses
-2x-6+10
We add all the numbers together, and all the variables
-2x+4
Back to the equation:
-(-2x+4)
We get rid of parentheses
4x+2x-4-20=0
We add all the numbers together, and all the variables
6x-24=0
We move all terms containing x to the left, all other terms to the right
6x=24
x=24/6
x=4

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