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(x+6)(3x-2)=5x+2x
We move all terms to the left:
(x+6)(3x-2)-(5x+2x)=0
We add all the numbers together, and all the variables
(x+6)(3x-2)-(+7x)=0
We get rid of parentheses
(x+6)(3x-2)-7x=0
We multiply parentheses ..
(+3x^2-2x+18x-12)-7x=0
We get rid of parentheses
3x^2-2x+18x-7x-12=0
We add all the numbers together, and all the variables
3x^2+9x-12=0
a = 3; b = 9; c = -12;
Δ = b2-4ac
Δ = 92-4·3·(-12)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-15}{2*3}=\frac{-24}{6} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+15}{2*3}=\frac{6}{6} =1 $
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