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4(x-5)+2=2(x-9)+2x*
We move all terms to the left:
4(x-5)+2-(2(x-9)+2x*)=0
We multiply parentheses
4x-(2(x-9)+2x*)-20+2=0
We calculate terms in parentheses: -(2(x-9)+2x*), so:We add all the numbers together, and all the variables
2(x-9)+2x*
We multiply parentheses
2x+2x*-18
Back to the equation:
-(2x+2x*-18)
4x-(2x+2x*-18)-18=0
We get rid of parentheses
4x-2x-2x*+18-18=0
We add all the numbers together, and all the variables
2x-2x*=0
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