2x-4(x-3)=2(x-10)

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Solution for 2x-4(x-3)=2(x-10) equation: 



2x-4(x-3)=2(x-10)

We move all terms to the left:

2x-4(x-3)-(2(x-10))=0

We multiply parentheses

2x-4x-(2(x-10))+12=0



We calculate terms in parentheses: -(2(x-10)), so:

2(x-10)

We multiply parentheses

2x-20

Back to the equation:

-(2x-20)



We add all the numbers together, and all the variables

-2x-(2x-20)+12=0

We get rid of parentheses

-2x-2x+20+12=0

We add all the numbers together, and all the variables

-4x+32=0

We move all terms containing x to the left, all other terms to the right

-4x=-32

x=-32/-4

x=+8

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