4(x-4)=8(3x-2)

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Solution for 4(x-4)=8(3x-2) equation:



4(x-4)=8(3x-2)
We move all terms to the left:
4(x-4)-(8(3x-2))=0
We multiply parentheses
4x-(8(3x-2))-16=0
We calculate terms in parentheses: -(8(3x-2)), so:
8(3x-2)
We multiply parentheses
24x-16
Back to the equation:
-(24x-16)
We get rid of parentheses
4x-24x+16-16=0
We add all the numbers together, and all the variables
-20x=0
x=0/-20
x=0

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