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9x(x+1)=88
We move all terms to the left:
9x(x+1)-(88)=0
We multiply parentheses
9x^2+9x-88=0
a = 9; b = 9; c = -88;
Δ = b2-4ac
Δ = 92-4·9·(-88)
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3249}=57$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-57}{2*9}=\frac{-66}{18} =-3+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+57}{2*9}=\frac{48}{18} =2+2/3 $
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