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4(x-4)-(x+7)=5(x-3)
We move all terms to the left:
4(x-4)-(x+7)-(5(x-3))=0
We multiply parentheses
4x-(x+7)-(5(x-3))-16=0
We get rid of parentheses
4x-x-(5(x-3))-7-16=0
We calculate terms in parentheses: -(5(x-3)), so:We add all the numbers together, and all the variables
5(x-3)
We multiply parentheses
5x-15
Back to the equation:
-(5x-15)
3x-(5x-15)-23=0
We get rid of parentheses
3x-5x+15-23=0
We add all the numbers together, and all the variables
-2x-8=0
We move all terms containing x to the left, all other terms to the right
-2x=8
x=8/-2
x=-4
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