-40(40-5x)=4(5x+50)

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Solution for -40(40-5x)=4(5x+50) equation: 



-40(40-5x)=4(5x+50)

We move all terms to the left:

-40(40-5x)-(4(5x+50))=0

We add all the numbers together, and all the variables

-40(-5x+40)-(4(5x+50))=0

We multiply parentheses

200x-(4(5x+50))-1600=0



We calculate terms in parentheses: -(4(5x+50)), so:

4(5x+50)

We multiply parentheses

20x+200

Back to the equation:

-(20x+200)



We get rid of parentheses

200x-20x-200-1600=0

We add all the numbers together, and all the variables

180x-1800=0

We move all terms containing x to the left, all other terms to the right

180x=1800

x=1800/180

x=10

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