4(x-4)+3x=5x+2(x-8)

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Solution for 4(x-4)+3x=5x+2(x-8) equation: 



4(x-4)+3x=5x+2(x-8)

We move all terms to the left:

4(x-4)+3x-(5x+2(x-8))=0

We add all the numbers together, and all the variables

3x+4(x-4)-(5x+2(x-8))=0

We multiply parentheses

3x+4x-(5x+2(x-8))-16=0



We calculate terms in parentheses: -(5x+2(x-8)), so:

5x+2(x-8)

We multiply parentheses

5x+2x-16

We add all the numbers together, and all the variables

7x-16

Back to the equation:

-(7x-16)



We add all the numbers together, and all the variables

7x-(7x-16)-16=0

We get rid of parentheses

7x-7x+16-16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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