4y-(2y+6/)=10

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Solution for 4y-(2y+6/)=10 equation: 



4y-(2y+6/)=10

We move all terms to the left:

4y-(2y+6/)-(10)=0

We add all the numbers together, and all the variables

4y-(+2y+6/)-10=0

We get rid of parentheses

4y-2y-10-6/=0

We multiply all the terms by the denominator


4y*-2y*-6-10*=0

We add all the numbers together, and all the variables

4y*-2y*=0

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