4(x-3)=8x-40

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Solution for 4(x-3)=8x-40 equation: 



4(x-3)=8x-40

We move all terms to the left:

4(x-3)-(8x-40)=0

We multiply parentheses

4x-(8x-40)-12=0

We get rid of parentheses

4x-8x+40-12=0

We add all the numbers together, and all the variables

-4x+28=0

We move all terms containing x to the left, all other terms to the right

-4x=-28

x=-28/-4

x=+7

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