4(x-3)=5(2x-4)=2

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Solution for 4(x-3)=5(2x-4)=2 equation: 



4(x-3)=5(2x-4)=2

We move all terms to the left:

4(x-3)-(5(2x-4))=0

We multiply parentheses

4x-(5(2x-4))-12=0



We calculate terms in parentheses: -(5(2x-4)), so:

5(2x-4)

We multiply parentheses

10x-20

Back to the equation:

-(10x-20)



We get rid of parentheses

4x-10x+20-12=0

We add all the numbers together, and all the variables

-6x+8=0

We move all terms containing x to the left, all other terms to the right

-6x=-8

x=-8/-6

x=1+1/3

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