(10+2-1)x=(4x2)-88

Solution for (10+2-1)x=(4x2)-88 equation:

(10+2-1)x=(4x^2)-88

We move all terms to the left:

(10+2-1)x-((4x^2)-88)=0

We add all the numbers together, and all the variables

11x-(4x^2-88)=0

We get rid of parentheses

-4x^2+11x+88=0

a = -4; b = 11; c = +88;
Δ = b2-4ac
Δ = 112-4·(-4)·88
Δ = 1529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{1529}}{2*-4}=\frac{-11-\sqrt{1529}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{1529}}{2*-4}=\frac{-11+\sqrt{1529}}{-8}
$