4(x-3)=2(-6+2x)

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Solution for 4(x-3)=2(-6+2x) equation: 



4(x-3)=2(-6+2x)

We move all terms to the left:

4(x-3)-(2(-6+2x))=0

We add all the numbers together, and all the variables

4(x-3)-(2(2x-6))=0

We multiply parentheses

4x-(2(2x-6))-12=0



We calculate terms in parentheses: -(2(2x-6)), so:

2(2x-6)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We get rid of parentheses

4x-4x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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