6x2+35x=19

Solution for 6x2+35x=19 equation:

6x^2+35x=19

We move all terms to the left:

6x^2+35x-(19)=0

a = 6; b = 35; c = -19;
Δ = b2-4ac
Δ = 352-4·6·(-19)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-41}{2*6}=\frac{-76}{12}
=-6+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+41}{2*6}=\frac{6}{12}
=1/2
$