4(x-3)=16-(x-2)

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Solution for 4(x-3)=16-(x-2) equation: 



4(x-3)=16-(x-2)

We move all terms to the left:

4(x-3)-(16-(x-2))=0

We multiply parentheses

4x-(16-(x-2))-12=0



We calculate terms in parentheses: -(16-(x-2)), so:

16-(x-2)

determiningTheFunctionDomain
-(x-2)+16

We get rid of parentheses

-x+2+16

We add all the numbers together, and all the variables

-1x+18

Back to the equation:

-(-1x+18)



We get rid of parentheses

4x+1x-18-12=0

We add all the numbers together, and all the variables

5x-30=0

We move all terms containing x to the left, all other terms to the right

5x=30

x=30/5

x=6

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