7(3-2f)-(11-4f)=8(2-5f)-(10-25f)

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Solution for 7(3-2f)-(11-4f)=8(2-5f)-(10-25f) equation:



7(3-2f)-(11-4f)=8(2-5f)-(10-25f)
We move all terms to the left:
7(3-2f)-(11-4f)-(8(2-5f)-(10-25f))=0
We add all the numbers together, and all the variables
7(-2f+3)-(-4f+11)-(8(-5f+2)-(-25f+10))=0
We multiply parentheses
-14f-(-4f+11)-(8(-5f+2)-(-25f+10))+21=0
We get rid of parentheses
-14f+4f-(8(-5f+2)-(-25f+10))-11+21=0
We calculate terms in parentheses: -(8(-5f+2)-(-25f+10)), so:
8(-5f+2)-(-25f+10)
We multiply parentheses
-40f-(-25f+10)+16
We get rid of parentheses
-40f+25f-10+16
We add all the numbers together, and all the variables
-15f+6
Back to the equation:
-(-15f+6)
We add all the numbers together, and all the variables
-10f-(-15f+6)+10=0
We get rid of parentheses
-10f+15f-6+10=0
We add all the numbers together, and all the variables
5f+4=0
We move all terms containing f to the left, all other terms to the right
5f=-4
f=-4/5
f=-4/5

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