4(x-3)=(x-3)-3(x-5)

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Solution for 4(x-3)=(x-3)-3(x-5) equation: 



4(x-3)=(x-3)-3(x-5)

We move all terms to the left:

4(x-3)-((x-3)-3(x-5))=0

We multiply parentheses

4x-((x-3)-3(x-5))-12=0



We calculate terms in parentheses: -((x-3)-3(x-5)), so:

(x-3)-3(x-5)

We multiply parentheses

(x-3)-3x+15

We get rid of parentheses

x-3x-3+15

We add all the numbers together, and all the variables

-2x+12

Back to the equation:

-(-2x+12)



We get rid of parentheses

4x+2x-12-12=0

We add all the numbers together, and all the variables

6x-24=0

We move all terms containing x to the left, all other terms to the right

6x=24

x=24/6

x=4

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