4(x-3)=2(x-1)+2(x-5)

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Solution for 4(x-3)=2(x-1)+2(x-5) equation: 



4(x-3)=2(x-1)+2(x-5)

We move all terms to the left:

4(x-3)-(2(x-1)+2(x-5))=0

We multiply parentheses

4x-(2(x-1)+2(x-5))-12=0



We calculate terms in parentheses: -(2(x-1)+2(x-5)), so:

2(x-1)+2(x-5)

We multiply parentheses

2x+2x-2-10

We add all the numbers together, and all the variables

4x-12

Back to the equation:

-(4x-12)



We get rid of parentheses

4x-4x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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