4(x-3)+36=64-(x+2)

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Solution for 4(x-3)+36=64-(x+2) equation:



4(x-3)+36=64-(x+2)
We move all terms to the left:
4(x-3)+36-(64-(x+2))=0
We multiply parentheses
4x-(64-(x+2))-12+36=0
We calculate terms in parentheses: -(64-(x+2)), so:
64-(x+2)
determiningTheFunctionDomain -(x+2)+64
We get rid of parentheses
-x-2+64
We add all the numbers together, and all the variables
-1x+62
Back to the equation:
-(-1x+62)
We add all the numbers together, and all the variables
4x-(-1x+62)+24=0
We get rid of parentheses
4x+1x-62+24=0
We add all the numbers together, and all the variables
5x-38=0
We move all terms containing x to the left, all other terms to the right
5x=38
x=38/5
x=7+3/5

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