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20.16=10x-x2
We move all terms to the left:
20.16-(10x-x2)=0
We add all the numbers together, and all the variables
-(+10x-1x^2)+20.16=0
We get rid of parentheses
1x^2-10x+20.16=0
We add all the numbers together, and all the variables
x^2-10x+20.16=0
a = 1; b = -10; c = +20.16;
Δ = b2-4ac
Δ = -102-4·1·20.16
Δ = 19.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-\sqrt{19.36}}{2*1}=\frac{10-\sqrt{19.36}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+\sqrt{19.36}}{2*1}=\frac{10+\sqrt{19.36}}{2} $
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