4(x-3)+2x=3(x+2)+x

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Solution for 4(x-3)+2x=3(x+2)+x equation: 



4(x-3)+2x=3(x+2)+x

We move all terms to the left:

4(x-3)+2x-(3(x+2)+x)=0

We add all the numbers together, and all the variables

2x+4(x-3)-(3(x+2)+x)=0

We multiply parentheses

2x+4x-(3(x+2)+x)-12=0



We calculate terms in parentheses: -(3(x+2)+x), so:

3(x+2)+x

We add all the numbers together, and all the variables

x+3(x+2)

We multiply parentheses

x+3x+6

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We add all the numbers together, and all the variables

6x-(4x+6)-12=0

We get rid of parentheses

6x-4x-6-12=0

We add all the numbers together, and all the variables

2x-18=0

We move all terms containing x to the left, all other terms to the right

2x=18

x=18/2

x=9

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