-3j-6(2j-10)=j+6+2j

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Solution for -3j-6(2j-10)=j+6+2j equation: 



-3j-6(2j-10)=j+6+2j

We move all terms to the left:

-3j-6(2j-10)-(j+6+2j)=0

We add all the numbers together, and all the variables

-3j-6(2j-10)-(3j+6)=0

We multiply parentheses

-3j-12j-(3j+6)+60=0

We get rid of parentheses

-3j-12j-3j-6+60=0

We add all the numbers together, and all the variables

-18j+54=0

We move all terms containing j to the left, all other terms to the right

-18j=-54

j=-54/-18

j=+3

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