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4(x-2)=5-(x-3)
We move all terms to the left:
4(x-2)-(5-(x-3))=0
We multiply parentheses
4x-(5-(x-3))-8=0
We calculate terms in parentheses: -(5-(x-3)), so:We get rid of parentheses
5-(x-3)
determiningTheFunctionDomain -(x-3)+5
We get rid of parentheses
-x+3+5
We add all the numbers together, and all the variables
-1x+8
Back to the equation:
-(-1x+8)
4x+1x-8-8=0
We add all the numbers together, and all the variables
5x-16=0
We move all terms containing x to the left, all other terms to the right
5x=16
x=16/5
x=3+1/5
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