4(x-2)=3(x+3)-11

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Solution for 4(x-2)=3(x+3)-11 equation: 



4(x-2)=3(x+3)-11

We move all terms to the left:

4(x-2)-(3(x+3)-11)=0

We multiply parentheses

4x-(3(x+3)-11)-8=0



We calculate terms in parentheses: -(3(x+3)-11), so:

3(x+3)-11

We multiply parentheses

3x+9-11

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We get rid of parentheses

4x-3x+2-8=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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