If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2c+2c+3=1+4c
We move all terms to the left:
2c+2c+3-(1+4c)=0
We add all the numbers together, and all the variables
2c+2c-(4c+1)+3=0
We add all the numbers together, and all the variables
4c-(4c+1)+3=0
We get rid of parentheses
4c-4c-1+3=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
| 12=9+x2 | | y2–12y=0 | | 7,8,x=7,9,x-1 | | 7b-4+5=6-5+7b | | 6a+9a=45 | | -6+3d=3(d+2) | | 5y+14=6y+3 | | 4x-8=5x-19=54 | | y-77/4=3 | | c2+7=86 | | 3(f-55)=78 | | 4a+9=2(6+2a) | | 6y-3y+12=5(7y-4) | | 6(3x-5)-4=2 | | w+24/9=3 | | -9-6c=-3(3+2c) | | 3d+5+2d-1=10+5d-6 | | 1/4(20x+16)+2x=20 | | 6(2b-6)=4(3b-9) | | 45=u/6+40 | | 5(3y+4)=20+10y | | 12w+17w+6=0 | | n/2+9=13 | | 4a+5-a=5+3a | | 16x-23=62 | | 30=(8+y) | | 5x+12=2x+35 | | 3x+47=x+9 | | 3x46-90-x=46 | | t+27+9t+33=180 | | x+2.25=4.46 | | t+27+9t+33=`180 |