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4(x-2)-2x=5-(4+x)
We move all terms to the left:
4(x-2)-2x-(5-(4+x))=0
We add all the numbers together, and all the variables
4(x-2)-2x-(5-(x+4))=0
We add all the numbers together, and all the variables
-2x+4(x-2)-(5-(x+4))=0
We multiply parentheses
-2x+4x-(5-(x+4))-8=0
We calculate terms in parentheses: -(5-(x+4)), so:We add all the numbers together, and all the variables
5-(x+4)
determiningTheFunctionDomain -(x+4)+5
We get rid of parentheses
-x-4+5
We add all the numbers together, and all the variables
-1x+1
Back to the equation:
-(-1x+1)
2x-(-1x+1)-8=0
We get rid of parentheses
2x+1x-1-8=0
We add all the numbers together, and all the variables
3x-9=0
We move all terms containing x to the left, all other terms to the right
3x=9
x=9/3
x=3
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