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a(a-1)=3(2+1)-3
We move all terms to the left:
a(a-1)-(3(2+1)-3)=0
We add all the numbers together, and all the variables
a(a-1)-(33-3)=0
We add all the numbers together, and all the variables
a(a-1)-30=0
We multiply parentheses
a^2-1a-30=0
a = 1; b = -1; c = -30;
Δ = b2-4ac
Δ = -12-4·1·(-30)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-11}{2*1}=\frac{-10}{2} =-5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+11}{2*1}=\frac{12}{2} =6 $
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