4(x-2)+3(x+3)=27

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Solution for 4(x-2)+3(x+3)=27 equation: 



4(x-2)+3(x+3)=27

We move all terms to the left:

4(x-2)+3(x+3)-(27)=0

We multiply parentheses

4x+3x-8+9-27=0

We add all the numbers together, and all the variables

7x-26=0

We move all terms containing x to the left, all other terms to the right

7x=26

x=26/7

x=3+5/7

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