(3x+1)+3x=19

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Solution for (3x+1)+3x=19 equation: 



(3x+1)+3x=19

We move all terms to the left:

(3x+1)+3x-(19)=0

We add all the numbers together, and all the variables

3x+(3x+1)-19=0

We get rid of parentheses

3x+3x+1-19=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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