4(x-2)+2x=3(x-4)-2

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Solution for 4(x-2)+2x=3(x-4)-2 equation: 



4(x-2)+2x=3(x-4)-2

We move all terms to the left:

4(x-2)+2x-(3(x-4)-2)=0

We add all the numbers together, and all the variables

2x+4(x-2)-(3(x-4)-2)=0

We multiply parentheses

2x+4x-(3(x-4)-2)-8=0



We calculate terms in parentheses: -(3(x-4)-2), so:

3(x-4)-2

We multiply parentheses

3x-12-2

We add all the numbers together, and all the variables

3x-14

Back to the equation:

-(3x-14)



We add all the numbers together, and all the variables

6x-(3x-14)-8=0

We get rid of parentheses

6x-3x+14-8=0

We add all the numbers together, and all the variables

3x+6=0

We move all terms containing x to the left, all other terms to the right

3x=-6

x=-6/3

x=-2

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