3(2x-5)+4(x+2)=12

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Solution for 3(2x-5)+4(x+2)=12 equation: 



3(2x-5)+4(x+2)=12

We move all terms to the left:

3(2x-5)+4(x+2)-(12)=0

We multiply parentheses

6x+4x-15+8-12=0

We add all the numbers together, and all the variables

10x-19=0

We move all terms containing x to the left, all other terms to the right

10x=19

x=19/10

x=1+9/10

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