4(x-1)=9x-3(x+1)-(8+x)

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Solution for 4(x-1)=9x-3(x+1)-(8+x) equation: 



4(x-1)=9x-3(x+1)-(8+x)

We move all terms to the left:

4(x-1)-(9x-3(x+1)-(8+x))=0

We add all the numbers together, and all the variables

4(x-1)-(9x-3(x+1)-(x+8))=0

We multiply parentheses

4x-(9x-3(x+1)-(x+8))-4=0



We calculate terms in parentheses: -(9x-3(x+1)-(x+8)), so:

9x-3(x+1)-(x+8)

We multiply parentheses

9x-3x-(x+8)-3

We get rid of parentheses

9x-3x-x-8-3

We add all the numbers together, and all the variables

5x-11

Back to the equation:

-(5x-11)



We get rid of parentheses

4x-5x+11-4=0

We add all the numbers together, and all the variables

-1x+7=0

We move all terms containing x to the left, all other terms to the right

-x=-7

x=-7/-1

x=+7

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