2(x-7)-3(x+2)=2-4(x+1)

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Solution for 2(x-7)-3(x+2)=2-4(x+1) equation: 



2(x-7)-3(x+2)=2-4(x+1)

We move all terms to the left:

2(x-7)-3(x+2)-(2-4(x+1))=0

We multiply parentheses

2x-3x-(2-4(x+1))-14-6=0



We calculate terms in parentheses: -(2-4(x+1)), so:

2-4(x+1)

determiningTheFunctionDomain
-4(x+1)+2

We multiply parentheses

-4x-4+2

We add all the numbers together, and all the variables

-4x-2

Back to the equation:

-(-4x-2)



We add all the numbers together, and all the variables

-1x-(-4x-2)-20=0

We get rid of parentheses

-1x+4x+2-20=0

We add all the numbers together, and all the variables

3x-18=0

We move all terms containing x to the left, all other terms to the right

3x=18

x=18/3

x=6

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