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w+12/3w+5=2/3
We move all terms to the left:
w+12/3w+5-(2/3)=0
Domain of the equation: 3w!=0We add all the numbers together, and all the variables
w!=0/3
w!=0
w∈R
w+12/3w+5-(+2/3)=0
We get rid of parentheses
w+12/3w+5-2/3=0
We calculate fractions
w+5=0
We move all terms containing w to the left, all other terms to the right
w=-5
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