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4(x-1)=3(2-2x)
We move all terms to the left:
4(x-1)-(3(2-2x))=0
We add all the numbers together, and all the variables
4(x-1)-(3(-2x+2))=0
We multiply parentheses
4x-(3(-2x+2))-4=0
We calculate terms in parentheses: -(3(-2x+2)), so:We get rid of parentheses
3(-2x+2)
We multiply parentheses
-6x+6
Back to the equation:
-(-6x+6)
4x+6x-6-4=0
We add all the numbers together, and all the variables
10x-10=0
We move all terms containing x to the left, all other terms to the right
10x=10
x=10/10
x=1
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