4(x-1)+x=3(x-2)+2

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Solution for 4(x-1)+x=3(x-2)+2 equation: 



4(x-1)+x=3(x-2)+2

We move all terms to the left:

4(x-1)+x-(3(x-2)+2)=0

We add all the numbers together, and all the variables

x+4(x-1)-(3(x-2)+2)=0

We multiply parentheses

x+4x-(3(x-2)+2)-4=0



We calculate terms in parentheses: -(3(x-2)+2), so:

3(x-2)+2

We multiply parentheses

3x-6+2

We add all the numbers together, and all the variables

3x-4

Back to the equation:

-(3x-4)



We add all the numbers together, and all the variables

5x-(3x-4)-4=0

We get rid of parentheses

5x-3x+4-4=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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